What is the answer to 9^{2x}*27^{x^2}=3^{-1} ?

The answer to 9^{2x}*27^{x^2}=3^{-1} is x=-1/3 ,x=-1

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9^{2x}*27^{x^2}=3^{-1}

9^{2 x} \cdot 2 7^{x^{2}} = 3^{- 1}

x = - \frac{1}{3}, x = - 1

Decimal Notation

x = - 0.33333 \dots, x = - 1

Solution steps

9^{2 x} \cdot 2 7^{x^{2}} = 3^{- 1}

Apply exponent rules

4 x + 3 x^{2} = - 1

Solve

4 x + 3 x^{2} = - 1 : x = - \frac{1}{3}, x = - 1

x = - \frac{1}{3}, x = - 1

e^{2 x} = 54

21 6^{2 x} \cdot 21 6^{3 - 2 x} = 36

5^{x + 2} = 125

y, e^{2 x y} + 2 y = 2 x + 2

What is the answer to 9^{2x}*27^{x^2}=3^{-1} ?
The answer to 9^{2x}*27^{x^2}=3^{-1} is x=-1/3 ,x=-1
Solve for x: 9^{2x}*27^{x^2}=3^{-1}
The solution is x=-1/3 ,x=-1