What is the answer to (1/2)^n=4^{(n+1)} ?

The answer to (1/2)^n=4^{(n+1)} is n=-2/3

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(1/2)^n=4^{(n+1)}

(\frac{1}{2})^{n} = 4^{(n + 1)}

n = - \frac{2}{3}

Decimal Notation

n = - 0.66666 \dots

Solution steps

(\frac{1}{2})^{n} = 4^{(n + 1)}

Apply exponent rules

- n = 2 (n + 1)

Solve

- n = 2 (n + 1) : n = - \frac{2}{3}

n = - \frac{2}{3}

2^{- x} = 4

2^{- x} = 8

e^{8 - 4 x} = 2

e^{8 - 4 x} = 3

e^{x} (x + 1) = 0

What is the answer to (1/2)^n=4^{(n+1)} ?
The answer to (1/2)^n=4^{(n+1)} is n=-2/3
Solve for n: (1/2)^n=4^{(n+1)}
The solution is n=-2/3