What are the solutions to the equation x^2+24=-11x ?

The solutions to the equation x^2+24=-11x are x=-3,x=-8

Find the zeros of x^2+24=-11x

The zeros of x^2+24=-11x are x=-3,x=-8

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x^{2} + 24 = - 11 x

x = - 3, x = - 8

Solution steps

x^{2} + 24 = - 11 x

Move

11 x

to the left side

x^{2} + 24 + 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 1}, x_{2} = \frac{- 11 - 5}{2 \cdot 1}

x = \frac{- 11 + 5}{2 \cdot 1} : - 3

x = \frac{- 11 - 5}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

- 4 - 7

x^{2} - 10 x - 5 = 0

2 + (- \frac{1}{2})

x^{2} - 10 = 9 x

∣ 7 v - 4 ∣ = - 14

What are the solutions to the equation x^2+24=-11x ?
The solutions to the equation x^2+24=-11x are x=-3,x=-8
Find the zeros of x^2+24=-11x
The zeros of x^2+24=-11x are x=-3,x=-8