What is the answer to 7^{3x-2}=13^{x+1} ?

The answer to 7^{3x-2}=13^{x+1} is x=(ln(637))/(3ln(7)-ln(13))

Solve for x: 7^{3x-2}=13^{x+1}

The solution is x=(ln(637))/(3ln(7)-ln(13))

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7^{3 x - 2} = 1 3^{x + 1}

x = \frac{ln ( 637 )}{3 ln ( 7 ) - ln ( 13 )}

Decimal Notation

x = 1.97286 \dots

Solution steps

7^{3 x - 2} = 1 3^{x + 1}

Apply exponent rules

(3 x - 2) ln (7) = (x + 1) ln (13)

Solve

(3 x - 2) ln (7) = (x + 1) ln (13) : x = \frac{ln ( 637 )}{3 ln ( 7 ) - ln ( 13 )}

x = \frac{ln ( 637 )}{3 ln ( 7 ) - ln ( 13 )}

5^{(2 x)} - 6 (5^{x}) + 5 = 0

I, x = e^{I n (7)}

0.1 e^{0.1 x} = 0.5

5 = 1000 (1 - \frac{1}{3})^{x}

(2)^{x} = 4

What is the answer to 7^{3x-2}=13^{x+1} ?
The answer to 7^{3x-2}=13^{x+1} is x=(ln(637))/(3ln(7)-ln(13))
Solve for x: 7^{3x-2}=13^{x+1}
The solution is x=(ln(637))/(3ln(7)-ln(13))