What is the answer to \sqrt[4]{8^{x-5}}=4^{4+2x} ?

The answer to \sqrt[4]{8^{x-5}}=4^{4+2x} is x=-47/13

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\sqrt[4]{8^{x-5}}=4^{4+2x}

x = - \frac{47}{13}

Decimal Notation

x = - 3.61538 \dots

Solution steps

Apply exponent rules

\frac{3}{4} (x - 5) = 2 (4 + 2 x)

Solve

\frac{3}{4} (x - 5) = 2 (4 + 2 x) : x = - \frac{47}{13}

x = - \frac{47}{13}

e^{x} - x^{3} = 0

4^{3 x} = 8^{x - 1}

e^{x} - 2 e^{- x} = 1

e^{5 x} = 4

3 x^{4} e^{- 2 l n (x)} + 2 x - 1 = 0

What is the answer to \sqrt[4]{8^{x-5}}=4^{4+2x} ?
The answer to \sqrt[4]{8^{x-5}}=4^{4+2x} is x=-47/13
Solve for x: \sqrt[4]{8^{x-5}}=4^{4+2x}
The solution is x=-47/13