What is the answer to \sqrt[4]{8^{x-5}}=4^{4+2x} ?

The answer to \sqrt[4]{8^{x-5}}=4^{4+2x} is x=-47/13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\sqrt[4]{8^{x-5}}=4^{4+2x}

x = - \frac{47}{13}

Solution steps

Apply exponent rules

\frac{3}{4} (x - 5) = 2 (4 + 2 x)

Solve

\frac{3}{4} (x - 5) = 2 (4 + 2 x) : x = - \frac{47}{13}

x = - \frac{47}{13}

e^{x} - x^{3} = 0

4^{3 x} = 8^{x - 1}

e^{x} - 2 e^{- x} = 1

e^{5 x} = 4

3 x^{4} e^{- 2 l n (x)} + 2 x - 1 = 0

What is the answer to \sqrt[4]{8^{x-5}}=4^{4+2x} ?
The answer to \sqrt[4]{8^{x-5}}=4^{4+2x} is x=-47/13
Solve for x: \sqrt[4]{8^{x-5}}=4^{4+2x}
The solution is x=-47/13