What is the answer to 4^{3x-1}=(0.5)^{-x-3} ?

The answer to 4^{3x-1}=(0.5)^{-x-3} is x=1

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4^{3x-1}=(0.5)^{-x-3}

4^{3 x - 1} = (0.5)^{- x - 3}

x = 1

Solution steps

4^{3 x - 1} = (0.5)^{- x - 3}

4^{3 x - 1} = (\frac{1}{2})^{- x - 3}

Apply exponent rules

2 (3 x - 1) = - (- x - 3)

Solve

2 (3 x - 1) = - (- x - 3) : x = 1

x = 1

e^{- x^{2} - y^{2}} x (1 - 2 y^{2}) = 0

\frac{n}{2 ^{x}} = 1

550 \cdot 3^{x} = 50

\frac{8 ^{x} + 1}{8 ^{x}} = 9

2^{y} = 32

What is the answer to 4^{3x-1}=(0.5)^{-x-3} ?
The answer to 4^{3x-1}=(0.5)^{-x-3} is x=1
Solve for x: 4^{3x-1}=(0.5)^{-x-3}
The solution is x=1