What is the answer to 27^{27^{x+1}}=3^{9^{x-2}} ?

The answer to 27^{27^{x+1}}=3^{9^{x-2}} is x=-8

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27^{27^{x+1}}=3^{9^{x-2}}

2 7^{2 7^{x + 1}} = 3^{9^{x - 2}}

x = - 8

Solution steps

2 7^{2 7^{x + 1}} = 3^{9^{x - 2}}

Apply exponent rules

1 + 3 (x + 1) = 2 (x - 2)

Solve

1 + 3 (x + 1) = 2 (x - 2) : x = - 8

x = - 8

\frac{3 ^{x}}{9 ^{3 x}} = 81

2 = 1.0 4^{x}

2^{m} = 0.125

4 x + 1 = 2^{3 x - 2}

e^{- 4 k - 10} = \frac{67}{6}

What is the answer to 27^{27^{x+1}}=3^{9^{x-2}} ?
The answer to 27^{27^{x+1}}=3^{9^{x-2}} is x=-8
Solve for x: 27^{27^{x+1}}=3^{9^{x-2}}
The solution is x=-8