What is the answer to \sqrt[x+2]{8}=\sqrt[2x-1]{32} ?

The answer to \sqrt[x+2]{8}=\sqrt[2x-1]{32} is x=13

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\sqrt[x+2]{8}=\sqrt[2x-1]{32}

x = 13

Solution steps

Apply exponent rules

\frac{3}{x + 2} = \frac{5}{2 x - 1}

Solve

\frac{3}{x + 2} = \frac{5}{2 x - 1} : x = 13

x = 13

(5)^{x} = 125

2^{2 x + 1} = 2^{4}

(\frac{1}{2})^{x} = 0.9

2^{2 x + 1} = 4^{x} + 64

e^{x} - 3 = 0

What is the answer to \sqrt[x+2]{8}=\sqrt[2x-1]{32} ?
The answer to \sqrt[x+2]{8}=\sqrt[2x-1]{32} is x=13
Solve for x: \sqrt[x+2]{8}=\sqrt[2x-1]{32}
The solution is x=13