What is the answer to 10^{2x}-2(10^x)+1=0 ?

The answer to 10^{2x}-2(10^x)+1=0 is x=0

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10^{2x}-2(10^x)+1=0

1 0^{2 x} - 2 (1 0^{x}) + 1 = 0

x = 0

Solution steps

1 0^{2 x} - 2 (1 0^{x}) + 1 = 0

Apply exponent rules

(1 0^{x})^{2} - 2 \cdot 1 0^{x} + 1 = 0

Rewrite the equation with

1 0^{x} = u

(u)^{2} - 2 u + 1 = 0

Solve

u^{2} - 2 u + 1 = 0 : u = 1

u = 1

Substitute back

u = 1 0^{x},

solve for

x

Solve

1 0^{x} = 1 : x = 0

x = 0

3^{5 x - 1} = 4^{3 x + 6}

(\frac{1}{16})^{x} = 64

1 0^{3 x} = 98

9 \cdot 2 7^{2 x - 4} = 81

A (t) = 30 e^{(0.02) t}

What is the answer to 10^{2x}-2(10^x)+1=0 ?
The answer to 10^{2x}-2(10^x)+1=0 is x=0
Solve for x: 10^{2x}-2(10^x)+1=0
The solution is x=0