What is the answer to 4*7^{2x}=9 ?

The answer to 4*7^{2x}=9 is x=(ln(9/4))/(2ln(7))

Solve for x: 4*7^{2x}=9

The solution is x=(ln(9/4))/(2ln(7))

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4 \cdot 7^{2 x} = 9

x = \frac{ln ( \frac{9}{4} )}{2 ln ( 7 )}

Solution steps

4 \cdot 7^{2 x} = 9

Divide both sides by

4

7^{2 x} = \frac{9}{4}

Apply exponent rules

2 x ln (7) = ln (\frac{9}{4})

Solve

2 x ln (7) = ln (\frac{9}{4}) : x = \frac{ln ( \frac{9}{4} )}{2 ln ( 7 )}

x = \frac{ln ( \frac{9}{4} )}{2 ln ( 7 )}

e^{x - 3} + e^{- x + 3} = 22

2^{9 x} = 5^{- x - 3}

e^{x + 1} = 9^{\frac{2 x}{3}}

e^{- x} - 2 x e^{x} = 0

5^{x} + 5^{x + 1} = 750

What is the answer to 4*7^{2x}=9 ?
The answer to 4*7^{2x}=9 is x=(ln(9/4))/(2ln(7))
Solve for x: 4*7^{2x}=9
The solution is x=(ln(9/4))/(2ln(7))