What is the answer to 3^{x^2}=(27)/(9^x) ?

The answer to 3^{x^2}=(27)/(9^x) is x=1,x=-3

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3^{x^2}=(27)/(9^x)

3^{x^{2}} = \frac{27}{9 ^{x}}

x = 1, x = - 3

Solution steps

3^{x^{2}} = \frac{27}{9 ^{x}}

Apply exponent rules

x^{2} = - 2 x + 3

Solve

x^{2} = - 2 x + 3 : x = 1, x = - 3

x = 1, x = - 3

Verify Solutions:

x = 1

True

, x = - 3

True

The solutions are

x = 1, x = - 3

2 = 4^{x}

(\frac{1}{3})^{x} = \frac{1}{27}

x, 4 \cdot 2^{5 x} = 64

(\frac{1}{2})^{x} = 2^{x + 3}

2^{x - 1} + 20 = 3 (2^{x})

What is the answer to 3^{x^2}=(27)/(9^x) ?
The answer to 3^{x^2}=(27)/(9^x) is x=1,x=-3
Solve for x: 3^{x^2}=(27)/(9^x)
The solution is x=1,x=-3