What is the answer to (13)/(2^x)=3^{x-5} ?

The answer to (13)/(2^x)=3^{x-5} is x=(ln(3159))/(ln(6))

Solve for x: (13)/(2^x)=3^{x-5}

The solution is x=(ln(3159))/(ln(6))

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\frac{13}{2 ^{x}} = 3^{x - 5}

x = \frac{ln ( 3159 )}{ln ( 6 )}

Solution steps

\frac{13}{2 ^{x}} = 3^{x - 5}

Apply exponent rules

ln (13) - x ln (2) = (x - 5) ln (3)

Solve

ln (13) - x ln (2) = (x - 5) ln (3) : x = \frac{ln ( 3159 )}{ln ( 6 )}

x = \frac{ln ( 3159 )}{ln ( 6 )}

Verify Solutions:

x = \frac{ln ( 3159 )}{ln ( 6 )}

True

The solution is

x = \frac{ln ( 3159 )}{ln ( 6 )}

2^{3 x + 5} = 32 (8)^{x}

x, e^{x} = 1

2^{4 x} = 127

x, e^{x} = 7

2 5^{x} - 23 \cdot 5^{x} = 50

What is the answer to (13)/(2^x)=3^{x-5} ?
The answer to (13)/(2^x)=3^{x-5} is x=(ln(3159))/(ln(6))
Solve for x: (13)/(2^x)=3^{x-5}
The solution is x=(ln(3159))/(ln(6))