What is the answer to 8^{2x-1}=3^{x-2} ?

The answer to 8^{2x-1}=3^{x-2} is x=(-2ln(3)+3ln(2))/(6ln(2)-ln(3))

Solve for x: 8^{2x-1}=3^{x-2}

The solution is x=(-2ln(3)+3ln(2))/(6ln(2)-ln(3))

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8^{2 x - 1} = 3^{x - 2}

x = \frac{- 2 ln ( 3 ) + 3 ln ( 2 )}{6 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = - 0.03848 \dots

Solution steps

8^{2 x - 1} = 3^{x - 2}

Apply exponent rules

(2 x - 1) ln (8) = (x - 2) ln (3)

Solve

(2 x - 1) ln (8) = (x - 2) ln (3) : x = \frac{- 2 ln ( 3 ) + 3 ln ( 2 )}{6 ln ( 2 ) - ln ( 3 )}

x = \frac{- 2 ln ( 3 ) + 3 ln ( 2 )}{6 ln ( 2 ) - ln ( 3 )}

3^{2 x + 1} - 4 (3^{3 x + 1}) + 1 = 0

1 0^{x} = 10

1 0^{x} = 24

1 0^{x} = 30

x \cdot e^{x} = 1

What is the answer to 8^{2x-1}=3^{x-2} ?
The answer to 8^{2x-1}=3^{x-2} is x=(-2ln(3)+3ln(2))/(6ln(2)-ln(3))
Solve for x: 8^{2x-1}=3^{x-2}
The solution is x=(-2ln(3)+3ln(2))/(6ln(2)-ln(3))