What are the solutions to the equation x^2-2x=-7/6 ?

The solutions to the equation x^2-2x=-7/6 are x=1+i(sqrt(6))/6 ,x=1-i(sqrt(6))/6

Find the zeros of x^2-2x=-7/6

The zeros of x^2-2x=-7/6 are x=1+i(sqrt(6))/6 ,x=1-i(sqrt(6))/6

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x^{2} - 2 x = - \frac{7}{6}

x = 1 + i \frac{6}{6}, x = 1 - i \frac{6}{6}

Solution steps

x^{2} - 2 x = - \frac{7}{6}

Multiply both sides by

6

6 x^{2} - 12 x = - 7

Move

7

to the left side

6 x^{2} - 12 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

Simplify

(- 12)^{2} - 4 \cdot 6 \cdot 7 : 26 i

x_{1, 2} = \frac{- ( - 12 ) \pm 2 6 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 6 i}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 2 6 i}{2 \cdot 6}

x = \frac{- ( - 12 ) + 2 6 i}{2 \cdot 6} : 1 + i \frac{6}{6}

x = \frac{- ( - 12 ) - 2 6 i}{2 \cdot 6} : 1 - i \frac{6}{6}

The solutions to the quadratic equation are:

x = 1 + i \frac{6}{6}, x = 1 - i \frac{6}{6}

x^{4} + 11 x^{2} + 30

3 ∣ 2 x - 7 ∣ + 5 = 9

2.2 b - 4 = - 0.15

- 3 \leq x - 2 < 1

3 x + 5 = 5 x - 9

What are the solutions to the equation x^2-2x=-7/6 ?
The solutions to the equation x^2-2x=-7/6 are x=1+i(sqrt(6))/6 ,x=1-i(sqrt(6))/6
Find the zeros of x^2-2x=-7/6
The zeros of x^2-2x=-7/6 are x=1+i(sqrt(6))/6 ,x=1-i(sqrt(6))/6