What is the answer to 5*4^{v-1}=92.8 ?

The answer to 5*4^{v-1}=92.8 is v=(ln(18.56))/(2ln(2))+1

Solve for v: 5*4^{v-1}=92.8

The solution is v=(ln(18.56))/(2ln(2))+1

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5 \cdot 4^{v - 1} = 92.8

v = \frac{ln ( 18.56 )}{2 ln ( 2 )} + 1

Decimal Notation

v = 3.10706 \dots

Solution steps

5 \cdot 4^{v - 1} = 92.8

Divide both sides by

5

4^{v - 1} = 18.56

Apply exponent rules

(v - 1) ln (4) = ln (18.56)

Solve

(v - 1) ln (4) = ln (18.56) : v = \frac{ln ( 18.56 )}{2 ln ( 2 )} + 1

v = \frac{ln ( 18.56 )}{2 ln ( 2 )} + 1

x, 3^{2 x} + 1 + 4 (3 x) - 15 = 0

x e^{2 x} = x e^{x + 3}

3^{3 n} \cdot 9^{- 2 n + 1} = 27

2 = 1. 1^{t}

15 = 45 e^{- 0.05 t}

What is the answer to 5*4^{v-1}=92.8 ?
The answer to 5*4^{v-1}=92.8 is v=(ln(18.56))/(2ln(2))+1
Solve for v: 5*4^{v-1}=92.8
The solution is v=(ln(18.56))/(2ln(2))+1