What is the answer to 5^{x+3}5^{2x-4}=125 ?

The answer to 5^{x+3}5^{2x-4}=125 is x= 4/3

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5^{x+3}5^{2x-4}=125

5^{x + 3} 5^{2 x - 4} = 125

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

5^{x + 3} \cdot 5^{2 x - 4} = 125

Apply exponent rules

3 x - 1 = 3

Solve

3 x - 1 = 3 : x = \frac{4}{3}

x = \frac{4}{3}

3^{3 x - 4} = 12

1 3^{x} = 1

1 3^{x} = 2

1 6^{x} - 5 (4^{x}) + 6 = 0

e^{x} = 4 x^{2 + 10}

What is the answer to 5^{x+3}5^{2x-4}=125 ?
The answer to 5^{x+3}5^{2x-4}=125 is x= 4/3
Solve for x: 5^{x+3}5^{2x-4}=125
The solution is x= 4/3