What is the answer to 5^{x^2}=17 ?

The answer to 5^{x^2}=17 is x=sqrt((ln(17))/(ln(5))),x=-sqrt((ln(17))/(ln(5)))

Solve for x: 5^{x^2}=17

The solution is x=sqrt((ln(17))/(ln(5))),x=-sqrt((ln(17))/(ln(5)))

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5^{x^{2}} = 17

x = \frac{ln ( 17 )}{ln ( 5 )}, x = - \frac{ln ( 17 )}{ln ( 5 )}

Solution steps

5^{x^{2}} = 17

Apply exponent rules

x^{2} ln (5) = ln (17)

Solve

x^{2} ln (5) = ln (17) : x = \frac{ln ( 17 )}{ln ( 5 )}, x = - \frac{ln ( 17 )}{ln ( 5 )}

x = \frac{ln ( 17 )}{ln ( 5 )}, x = - \frac{ln ( 17 )}{ln ( 5 )}

x, 0 = e^{x}

3^{x + 2} = 9^{2 x - 3}

3^{x} = 8 1^{2}

- 4.4 \cdot 1 7^{- 4 x} = - 78

What is the answer to 5^{x^2}=17 ?
The answer to 5^{x^2}=17 is x=sqrt((ln(17))/(ln(5))),x=-sqrt((ln(17))/(ln(5)))
Solve for x: 5^{x^2}=17
The solution is x=sqrt((ln(17))/(ln(5))),x=-sqrt((ln(17))/(ln(5)))