What is the answer to 3^{x-x^2}= 1/(9^x) ?

The answer to 3^{x-x^2}= 1/(9^x) is x=0,x=3

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3^{x-x^2}= 1/(9^x)

3^{x - x^{2}} = \frac{1}{9 ^{x}}

x = 0, x = 3

Solution steps

3^{x - x^{2}} = \frac{1}{9 ^{x}}

Apply exponent rules

x - x^{2} = - 2 x

Solve

x - x^{2} = - 2 x : x = 0, x = 3

x = 0, x = 3

Verify Solutions:

x = 0

True

, x = 3

True

The solutions are

x = 0, x = 3

7^{x} = 4 9^{2}

e^{x} = - \frac{1}{2}

4 9^{3 x} = 34 3^{2 x + 1}

\frac{e ^{x} + 1}{2} = 7

8^{x - 1} = 16

What is the answer to 3^{x-x^2}= 1/(9^x) ?
The answer to 3^{x-x^2}= 1/(9^x) is x=0,x=3
Solve for x: 3^{x-x^2}= 1/(9^x)
The solution is x=0,x=3