What is the answer to 12^{2x}=4*3^{x+1} ?

The answer to 12^{2x}=4*3^{x+1} is x=(ln(12))/(ln(48))

Solve for x: 12^{2x}=4*3^{x+1}

The solution is x=(ln(12))/(ln(48))

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1 2^{2 x} = 4 \cdot 3^{x + 1}

x = \frac{ln ( 12 )}{ln ( 48 )}

Decimal Notation

x = 0.64189 \dots

Solution steps

1 2^{2 x} = 4 \cdot 3^{x + 1}

Apply exponent rules

2 x ln (12) = ln (4) + (x + 1) ln (3)

Solve

2 x ln (12) = ln (4) + (x + 1) ln (3) : x = \frac{ln ( 12 )}{ln ( 48 )}

x = \frac{ln ( 12 )}{ln ( 48 )}

6^{(x + 2)} = 21

3^{2 - x} = \frac{1}{81}

e^{x} = 2 x + 3

2^{3 x - 4} = 10

(5 y)^{y} = 5^{5^{5}}

What is the answer to 12^{2x}=4*3^{x+1} ?
The answer to 12^{2x}=4*3^{x+1} is x=(ln(12))/(ln(48))
Solve for x: 12^{2x}=4*3^{x+1}
The solution is x=(ln(12))/(ln(48))