What is the answer to 2^{2x+2}-3*2^{x+2}+8=0 ?

The answer to 2^{2x+2}-3*2^{x+2}+8=0 is x=1,x=0

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2^{2x+2}-3*2^{x+2}+8=0

2^{2 x + 2} - 3 \cdot 2^{x + 2} + 8 = 0

x = 1, x = 0

Solution steps

2^{2 x + 2} - 3 \cdot 2^{x + 2} + 8 = 0

Apply exponent rules

(2^{x})^{2} \cdot 2^{2} - 3 \cdot 2^{x} \cdot 2^{2} + 8 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} \cdot 2^{2} - 3 u \cdot 2^{2} + 8 = 0

Solve

u^{2} \cdot 2^{2} - 3 u \cdot 2^{2} + 8 = 0 : u = 2, u = 1

u = 2, u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 2 : x = 1

Solve

2^{x} = 1 : x = 0

x = 1, x = 0

4^{2 x} - 20 (4^{x}) + 64 = 0

3 (9^{k}) + 2 (4^{k}) = 5 (6^{k})

3^{2 x + 1} = \frac{1}{81}

0.5 \cdot e^{4 z} = 13

3^{x - 1} + 3^{x} + 3^{x - 1} = 26

What is the answer to 2^{2x+2}-3*2^{x+2}+8=0 ?
The answer to 2^{2x+2}-3*2^{x+2}+8=0 is x=1,x=0
Solve for x: 2^{2x+2}-3*2^{x+2}+8=0
The solution is x=1,x=0