What is the answer to 2^x=5^{1-x} ?

The answer to 2^x=5^{1-x} is x=(ln(5))/(ln(10))

Solve for x: 2^x=5^{1-x}

The solution is x=(ln(5))/(ln(10))

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2^{x} = 5^{1 - x}

x = \frac{ln ( 5 )}{ln ( 10 )}

Decimal Notation

x = 0.69897 \dots

Solution steps

2^{x} = 5^{1 - x}

Apply exponent rules

x ln (2) = (1 - x) ln (5)

Solve

x ln (2) = (1 - x) ln (5) : x = \frac{ln ( 5 )}{ln ( 10 )}

x = \frac{ln ( 5 )}{ln ( 10 )}

2^{3 x - 5} = 1024

e^{t^{2}} = 4

e^{(x^{2} - 16)} = 20

e^{x} = 100

2^{3 x - 2} = 3^{2 x + 1}

What is the answer to 2^x=5^{1-x} ?
The answer to 2^x=5^{1-x} is x=(ln(5))/(ln(10))
Solve for x: 2^x=5^{1-x}
The solution is x=(ln(5))/(ln(10))