What is the answer to 50=10(5+2)^{x-1} ?

The answer to 50=10(5+2)^{x-1} is x=(ln(5))/(ln(7))+1

Solve for x: 50=10(5+2)^{x-1}

The solution is x=(ln(5))/(ln(7))+1

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50 = 10 (5 + 2)^{x - 1}

x = \frac{ln ( 5 )}{ln ( 7 )} + 1

Solution steps

50 = 10 (5 + 2)^{x - 1}

Switch sides

10 (5 + 2)^{x - 1} = 50

Divide both sides by

10

(5 + 2)^{x - 1} = 5

Apply exponent rules

(x - 1) ln (5 + 2) = ln (5)

Solve

(x - 1) ln (5 + 2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 7 )} + 1

x = \frac{ln ( 5 )}{ln ( 7 )} + 1

6 e^{- 4 t} = 2

e^{2 x} - 4 e^{x} + 4 = 0

2^{x} + 4 x + 12 = 0

5 e^{2 - x} = 1 0^{x + 4}

- (16 x - 16) e^{- x} = 0

What is the answer to 50=10(5+2)^{x-1} ?
The answer to 50=10(5+2)^{x-1} is x=(ln(5))/(ln(7))+1
Solve for x: 50=10(5+2)^{x-1}
The solution is x=(ln(5))/(ln(7))+1