What is the answer to 3^x2^{1-x}=10 ?

The answer to 3^x2^{1-x}=10 is x=(ln(5))/(ln(3)-ln(2))

Solve for x: 3^x2^{1-x}=10

The solution is x=(ln(5))/(ln(3)-ln(2))

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3^{x} 2^{1 - x} = 10

x = \frac{ln ( 5 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 3.96936 \dots

Solution steps

3^{x} \cdot 2^{1 - x} = 10

Apply exponent rules

(lo g_{2} (3) x + 1 - x) ln (2) = ln (10)

Solve

(lo g_{2} (3) x + 1 - x) ln (2) = ln (10) : x = \frac{ln ( 5 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 5 )}{ln ( 3 ) - ln ( 2 )}

0 = - e^{3 x} + 3

x^{x} (ln (x) + 1) = 0

4^{x^{2}} \cdot 4^{5 x - 3} = 64

27 m^{3 x} = 1

2^{c} = 65536

What is the answer to 3^x2^{1-x}=10 ?
The answer to 3^x2^{1-x}=10 is x=(ln(5))/(ln(3)-ln(2))
Solve for x: 3^x2^{1-x}=10
The solution is x=(ln(5))/(ln(3)-ln(2))