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Popular >

20=25e^{-0.00012t}

Solution

20 = 25 e^{- 0.00012 t}

Solution

t = - \frac{ln ( \frac{4}{5} )}{0.00012}

+1

Decimal Notation

t = 1859.52959 \dots

Solution steps

20 = 25 e^{- 0.00012 t}

Switch sides

25 e^{- 0.00012 t} = 20

Divide both sides by

25

e^{- 0.00012 t} = \frac{4}{5}

Apply exponent rules

- 0.00012 t = ln (\frac{4}{5})

Solve

- 0.00012 t = ln (\frac{4}{5}) : t = - \frac{ln ( \frac{4}{5} )}{0.00012}

t = - \frac{ln ( \frac{4}{5} )}{0.00012}

Popular Examples

4^{x+1}+4^{x+2}=128

4^{x + 1} + 4^{x + 2} = 128

8e^{4x}-32e^{-4x}=0

8 e^{4 x} - 32 e^{- 4 x} = 0

3^{2 x} = 2 e^{x}

2^{n} = 10

2^{3 x} - 2^{x} = 120

Frequently Asked Questions (FAQ)

What is the answer to 20=25e^{-0.00012t} ?
The answer to 20=25e^{-0.00012t} is t=-(ln(4/5))/(0.00012)