What is the answer to 1.01^x=2 ?

The answer to 1.01^x=2 is x=(ln(2))/(ln(1.01))

Solve for x: 1.01^x=2

The solution is x=(ln(2))/(ln(1.01))

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1.0 1^{x} = 2

x = \frac{ln ( 2 )}{ln ( 1.01 )}

Decimal Notation

x = 69.66071 \dots

Solution steps

1.0 1^{x} = 2

Apply exponent rules

x ln (1.01) = ln (2)

Solve

x ln (1.01) = ln (2) : x = \frac{ln ( 2 )}{ln ( 1.01 )}

x = \frac{ln ( 2 )}{ln ( 1.01 )}

x, y + e^{y} = (x + C) e^{- x}

2. 3^{x} = 3^{5} + 17. 3^{5}

6^{2 n + 1} + 6^{2} = 6^{n} + 6^{n + 3}

x^{l o g_{10} (4 x)} = 256

i, x^{i} = 2