What is the answer to 2(7^y)=3-5sqrt(7^y) ?

The answer to 2(7^y)=3-5sqrt(7^y) is y=-(2ln(2))/(ln(7))

Solve for y: 2(7^y)=3-5sqrt(7^y)

The solution is y=-(2ln(2))/(ln(7))

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2 (7^{y}) = 3 - 5 7^{y}

y = - \frac{2 ln ( 2 )}{ln ( 7 )}

Decimal Notation

y = - 0.71241 \dots

Solution steps

2 (7^{y}) = 3 - 5 7^{y}

Rewrite the equation with

7^{y} = u

2 u = 3 - 5 u

Solve

2 u = 3 - 5 u : u = \frac{1}{4}

u = \frac{1}{4}

Substitute back

u = 7^{y},

solve for

y

Solve

7^{y} = \frac{1}{4} : y = - \frac{2 ln ( 2 )}{ln ( 7 )}

y = - \frac{2 ln ( 2 )}{ln ( 7 )}

- 2 = 2^{x}

16 = 5 + 16 e^{34 k}

3^{y} = \frac{1}{81}

3^{2 x} - 6 \cdot 3^{x} + 8 = 0

22.33 = 16 + 5 4^{- k (25)}

What is the answer to 2(7^y)=3-5sqrt(7^y) ?
The answer to 2(7^y)=3-5sqrt(7^y) is y=-(2ln(2))/(ln(7))
Solve for y: 2(7^y)=3-5sqrt(7^y)
The solution is y=-(2ln(2))/(ln(7))