What is the answer to 4^{x+3}=\sqrt[4]{8^{x+5}} ?

The answer to 4^{x+3}=\sqrt[4]{8^{x+5}} is x=-9/5

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4^{x+3}=\sqrt[4]{8^{x+5}}

x = - \frac{9}{5}

Decimal Notation

x = - 1.8

Solution steps

Apply exponent rules

2 (x + 3) = \frac{3}{4} (x + 5)

Solve

2 (x + 3) = \frac{3}{4} (x + 5) : x = - \frac{9}{5}

x = - \frac{9}{5}

3^{2 x} + 3^{x} = 2

x, 2 7^{x} = 9 (3^{y})

2^{3 x + 9} = 8^{x + 3}

2^{2} x - 2^{x} + 3 + 2^{4} = 0

e^{- 10 a - 4} = 45

What is the answer to 4^{x+3}=\sqrt[4]{8^{x+5}} ?
The answer to 4^{x+3}=\sqrt[4]{8^{x+5}} is x=-9/5
Solve for x: 4^{x+3}=\sqrt[4]{8^{x+5}}
The solution is x=-9/5