What is the answer to 4^{1+2x}*3^{4x+1}=432 ?

The answer to 4^{1+2x}*3^{4x+1}=432 is x= 1/2

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4^{1+2x}*3^{4x+1}=432

4^{1 + 2 x} \cdot 3^{4 x + 1} = 432

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

4^{1 + 2 x} \cdot 3^{4 x + 1} = 432

Apply exponent rules

(lo g_{3} (4) (1 + 2 x) + 4 x + 1) ln (3) = ln (432)

Solve

(lo g_{3} (4) (1 + 2 x) + 4 x + 1) ln (3) = ln (432) : x = \frac{1}{2}

x = \frac{1}{2}

x, 4 - 3^{x} = 0

128 = 2^{n}

\frac{( 8 ^{x} ) ^{x}}{3 2 ^{x}} = 4

28 \cdot 3^{5 x} = 252

5 \cdot 6^{x + 7} = 8 \cdot 9^{x - 10}

What is the answer to 4^{1+2x}*3^{4x+1}=432 ?
The answer to 4^{1+2x}*3^{4x+1}=432 is x= 1/2
Solve for x: 4^{1+2x}*3^{4x+1}=432
The solution is x= 1/2