What is the answer to 4^{3x-2}=7^{x+3} ?

The answer to 4^{3x-2}=7^{x+3} is x=(ln(5488))/(6ln(2)-ln(7))

Solve for x: 4^{3x-2}=7^{x+3}

The solution is x=(ln(5488))/(6ln(2)-ln(7))

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4^{3 x - 2} = 7^{x + 3}

x = \frac{ln ( 5488 )}{6 ln ( 2 ) - ln ( 7 )}

Decimal Notation

x = 3.89083 \dots

Solution steps

4^{3 x - 2} = 7^{x + 3}

Apply exponent rules

(3 x - 2) ln (4) = (x + 3) ln (7)

Solve

(3 x - 2) ln (4) = (x + 3) ln (7) : x = \frac{ln ( 5488 )}{6 ln ( 2 ) - ln ( 7 )}

x = \frac{ln ( 5488 )}{6 ln ( 2 ) - ln ( 7 )}

3^{2 x + 1} = 243

x, 93 = 2 3^{x}

2.1 (1.05)^{- 2 x} = 5.73

x, e^{x} - 4 y^{2} = c

2^{x} - 10 (2^{- x}) + 3 = 0

What is the answer to 4^{3x-2}=7^{x+3} ?
The answer to 4^{3x-2}=7^{x+3} is x=(ln(5488))/(6ln(2)-ln(7))
Solve for x: 4^{3x-2}=7^{x+3}
The solution is x=(ln(5488))/(6ln(2)-ln(7))