What is the answer to 2^{2x-1}=5^{3-x} ?

The answer to 2^{2x-1}=5^{3-x} is x=(ln(250))/(ln(20))

Solve for x: 2^{2x-1}=5^{3-x}

The solution is x=(ln(250))/(ln(20))

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2^{2 x - 1} = 5^{3 - x}

x = \frac{ln ( 250 )}{ln ( 20 )}

Decimal Notation

x = 1.84310 \dots

Solution steps

2^{2 x - 1} = 5^{3 - x}

Apply exponent rules

(2 x - 1) ln (2) = (3 - x) ln (5)

Solve

(2 x - 1) ln (2) = (3 - x) ln (5) : x = \frac{ln ( 250 )}{ln ( 20 )}

x = \frac{ln ( 250 )}{ln ( 20 )}

4^{x + 3} = 6^{x}

16 - 5 \cdot 2^{x} + 4^{x - 1} = 0

9^{x} = 3^{x - 1}

x, 4^{x} = 10 - 4^{x + 1}

3 e^{3 t} - 2 = 0

What is the answer to 2^{2x-1}=5^{3-x} ?
The answer to 2^{2x-1}=5^{3-x} is x=(ln(250))/(ln(20))
Solve for x: 2^{2x-1}=5^{3-x}
The solution is x=(ln(250))/(ln(20))