What is the answer to 3^{2x-3}=27^{((x+1))/2} ?

The answer to 3^{2x-3}=27^{((x+1))/2} is x=9

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3^{2x-3}=27^{((x+1))/2}

3^{2 x - 3} = 2 7^{\frac{( x + 1 )}{2}}

x = 9

Solution steps

3^{2 x - 3} = 2 7^{\frac{( x + 1 )}{2}}

Apply exponent rules

2 x - 3 = \frac{3 ( x + 1 )}{2}

Solve

2 x - 3 = \frac{3 ( x + 1 )}{2} : x = 9

x = 9

12 \cdot 1 0^{x} - 144 = 0

3 x e^{x} - 1 = 0

2^{X + 3} + 4^{X + 1} = 320

24 = e^{6 k}

24 3^{x} = 9

What is the answer to 3^{2x-3}=27^{((x+1))/2} ?
The answer to 3^{2x-3}=27^{((x+1))/2} is x=9
Solve for x: 3^{2x-3}=27^{((x+1))/2}
The solution is x=9