What is the answer to 2^{x-1}=3^{2x} ?

The answer to 2^{x-1}=3^{2x} is x=(ln(2))/(ln(2)-2ln(3))

Solve for x: 2^{x-1}=3^{2x}

The solution is x=(ln(2))/(ln(2)-2ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x - 1} = 3^{2 x}

x = \frac{ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

Decimal Notation

x = - 0.46084 \dots

Solution steps

2^{x - 1} = 3^{2 x}

Apply exponent rules

(x - 1) ln (2) = 2 x ln (3)

Solve

(x - 1) ln (2) = 2 x ln (3) : x = \frac{ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

x = \frac{ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

3^{x + 1} = 3^{3}

4^{(7 x - 2)} = 1 7^{(x + 1)}

e^{x - 1} - x - 1 = 0

e^{3 x} - 3 e^{2 x} + 4 e^{x} - 4 = 0

3^{2 x} = 3^{x + 5}

What is the answer to 2^{x-1}=3^{2x} ?
The answer to 2^{x-1}=3^{2x} is x=(ln(2))/(ln(2)-2ln(3))
Solve for x: 2^{x-1}=3^{2x}
The solution is x=(ln(2))/(ln(2)-2ln(3))