What is the answer to 9^{x^2-7x}=27^{x^2+5} ?

The answer to 9^{x^2-7x}=27^{x^2+5} is x=-7-sqrt(34),x=-7+sqrt(34)

Solve for x: 9^{x^2-7x}=27^{x^2+5}

The solution is x=-7-sqrt(34),x=-7+sqrt(34)

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9^{x^{2} - 7 x} = 2 7^{x^{2} + 5}

x = - 7 - 34, x = - 7 + 34

Decimal Notation

x = - 12.83095 \dots, x = - 1.16904 \dots

Solution steps

9^{x^{2} - 7 x} = 2 7^{x^{2} + 5}

Apply exponent rules

2 (x^{2} - 7 x) = 3 (x^{2} + 5)

Solve

2 (x^{2} - 7 x) = 3 (x^{2} + 5) : x = - 7 - 34, x = - 7 + 34

x = - 7 - 34, x = - 7 + 34

16 = 2^{x - 3}

x, e^{x y} + x y = 2

7^{5 x + 7} = 3

1 1^{2 x} = 12 1^{3 x + 1}

12 5^{3 x - 4} = 62 5^{- 3}

What is the answer to 9^{x^2-7x}=27^{x^2+5} ?
The answer to 9^{x^2-7x}=27^{x^2+5} is x=-7-sqrt(34),x=-7+sqrt(34)
Solve for x: 9^{x^2-7x}=27^{x^2+5}
The solution is x=-7-sqrt(34),x=-7+sqrt(34)