What is the answer to 3^{-x-1}=9^{2x+1} ?

The answer to 3^{-x-1}=9^{2x+1} is x=-3/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{-x-1}=9^{2x+1}

3^{- x - 1} = 9^{2 x + 1}

x = - \frac{3}{5}

Decimal Notation

x = - 0.6

Solution steps

3^{- x - 1} = 9^{2 x + 1}

Apply exponent rules

- x - 1 = 2 (2 x + 1)

Solve

- x - 1 = 2 (2 x + 1) : x = - \frac{3}{5}

x = - \frac{3}{5}

25 6^{1 - x} = 6 4^{2 x - 2}

\frac{e ^{x}}{x} = 0

4^{x + 2} = (2 \cdot 8)^{- 2}

- 2 \cdot 5^{2 x - 1} + 3 = - 21

5^{x} - 6 (5)^{x} + 5 = 0

What is the answer to 3^{-x-1}=9^{2x+1} ?
The answer to 3^{-x-1}=9^{2x+1} is x=-3/5
Solve for x: 3^{-x-1}=9^{2x+1}
The solution is x=-3/5