What is the answer to 8^{6x^2+4x}=4^{9x^2-9x+6} ?

The answer to 8^{6x^2+4x}=4^{9x^2-9x+6} is x= 2/5

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8^{6x^2+4x}=4^{9x^2-9x+6}

8^{6 x^{2} + 4 x} = 4^{9 x^{2} - 9 x + 6}

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

8^{6 x^{2} + 4 x} = 4^{9 x^{2} - 9 x + 6}

Apply exponent rules

3 (6 x^{2} + 4 x) = 2 (9 x^{2} - 9 x + 6)

Solve

3 (6 x^{2} + 4 x) = 2 (9 x^{2} - 9 x + 6) : x = \frac{2}{5}

x = \frac{2}{5}

0. 1^{x} = 10

n, (1 + i)^{n} = 32 i

2^{x} = 46

(e^{2})^{3 x} = e^{2 x} e^{3 x}

2^{x} = 30

What is the answer to 8^{6x^2+4x}=4^{9x^2-9x+6} ?
The answer to 8^{6x^2+4x}=4^{9x^2-9x+6} is x= 2/5
Solve for x: 8^{6x^2+4x}=4^{9x^2-9x+6}
The solution is x= 2/5