What is the answer to 3^{x-1}+3^{1+x}-3^x=63 ?

The answer to 3^{x-1}+3^{1+x}-3^x=63 is x=3

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3^{x-1}+3^{1+x}-3^x=63

3^{x - 1} + 3^{1 + x} - 3^{x} = 63

x = 3

Solution steps

3^{x - 1} + 3^{1 + x} - 3^{x} = 63

Factor

3^{x - 1} + 3^{1 + x} - 3^{x} : 7 \cdot 3^{x - 1}

7 \cdot 3^{x - 1} = 63

Divide both sides by

7

3^{x - 1} = 9

Apply exponent rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

5^{x^{2}} \cdot 5^{4} = 5^{5 x}

2^{2 x} - 10 \cdot 2^{x} + 2^{4} = 0

27 (3^{2 x}) + 134 (3^{x}) - 5 = 0

2 = 1.0 8^{x}

4^{x - 3} = 2^{x - 1}

What is the answer to 3^{x-1}+3^{1+x}-3^x=63 ?
The answer to 3^{x-1}+3^{1+x}-3^x=63 is x=3
Solve for x: 3^{x-1}+3^{1+x}-3^x=63
The solution is x=3