What is the answer to 3^{2x+1}=5^{x+1} ?

The answer to 3^{2x+1}=5^{x+1} is x=(ln(5)-ln(3))/(2ln(3)-ln(5))

Solve for x: 3^{2x+1}=5^{x+1}

The solution is x=(ln(5)-ln(3))/(2ln(3)-ln(5))

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3^{2 x + 1} = 5^{x + 1}

x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = 0.86906 \dots

Solution steps

3^{2 x + 1} = 5^{x + 1}

Apply exponent rules

(2 x + 1) ln (3) = (x + 1) ln (5)

Solve

(2 x + 1) ln (3) = (x + 1) ln (5) : x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 5 ) - ln ( 3 )}{2 ln ( 3 ) - ln ( 5 )}

x, f (2 e^{x} + 1) = 3

4^{3 x + 1} = 2

e^{4 x} = 81

3^{2 x + 1} - (16) 3^{x} + 5 = 0

4 = 240 1^{x} - 3

What is the answer to 3^{2x+1}=5^{x+1} ?
The answer to 3^{2x+1}=5^{x+1} is x=(ln(5)-ln(3))/(2ln(3)-ln(5))
Solve for x: 3^{2x+1}=5^{x+1}
The solution is x=(ln(5)-ln(3))/(2ln(3)-ln(5))