What are the solutions to the equation x^2-5x+25/4 =0 ?

The solutions to the equation x^2-5x+25/4 =0 are x= 5/2

Find the zeros of x^2-5x+25/4 =0

The zeros of x^2-5x+25/4 =0 are x= 5/2

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x^{2} - 5 x + \frac{25}{4} = 0

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

x^{2} - 5 x + \frac{25}{4} = 0

Multiply both sides by

4

4 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

f = - 2^{2}

\frac{5 ^{2}}{5 ^{- 7}}

k^{2} - 8 k + 7

5 x^{2} - 9 x - 18

\frac{( n - 1 ) !}{( n + 1 ) !}

What are the solutions to the equation x^2-5x+25/4 =0 ?
The solutions to the equation x^2-5x+25/4 =0 are x= 5/2
Find the zeros of x^2-5x+25/4 =0
The zeros of x^2-5x+25/4 =0 are x= 5/2