What is the answer to (27)/(9^x)=3^{x-1} ?

The answer to (27)/(9^x)=3^{x-1} is x= 4/3

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(27)/(9^x)=3^{x-1}

\frac{27}{9 ^{x}} = 3^{x - 1}

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

\frac{27}{9 ^{x}} = 3^{x - 1}

Apply exponent rules

- 2 x + 3 = x - 1

Solve

- 2 x + 3 = x - 1 : x = \frac{4}{3}

x = \frac{4}{3}

Verify Solutions:

x = \frac{4}{3}

True

The solution is

x = \frac{4}{3}

3 6^{2 x - 7} = 6^{x - 5}

3^{x + 1} - 2 = 25

8^{x^{2}} = 9^{x}

θ, r = φ e^{- θ} + ω θ e^{- θ}

3^{x} = 81

What is the answer to (27)/(9^x)=3^{x-1} ?
The answer to (27)/(9^x)=3^{x-1} is x= 4/3
Solve for x: (27)/(9^x)=3^{x-1}
The solution is x= 4/3