What is the answer to 2^{x^2}-4^{3x-4}=0 ?

The answer to 2^{x^2}-4^{3x-4}=0 is x=4,x=2

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2^{x^2}-4^{3x-4}=0

2^{x^{2}} - 4^{3 x - 4} = 0

x = 4, x = 2

Solution steps

2^{x^{2}} - 4^{3 x - 4} = 0

Add

4^{3 x - 4}

to both sides

2^{x^{2}} - 4^{3 x - 4} + 4^{3 x - 4} = 0 + 4^{3 x - 4}

Simplify

2^{x^{2}} = 4^{3 x - 4}

Apply exponent rules

x^{2} = 2 (3 x - 4)

Solve

x^{2} = 2 (3 x - 4) : x = 4, x = 2

x = 4, x = 2

(x) = 3^{- x}

x, x + y + e^{x y} = 0

2^{2 x + 1} = 3 (2^{x}) + 2

3^{x} + 16 = 9 \cdot 3^{x}

What is the answer to 2^{x^2}-4^{3x-4}=0 ?
The answer to 2^{x^2}-4^{3x-4}=0 is x=4,x=2
Solve for x: 2^{x^2}-4^{3x-4}=0
The solution is x=4,x=2