What is the answer to 4^{v+9}+5=38 ?

The answer to 4^{v+9}+5=38 is v=(ln(33))/(2ln(2))-9

Solve for v: 4^{v+9}+5=38

The solution is v=(ln(33))/(2ln(2))-9

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4^{v + 9} + 5 = 38

v = \frac{ln ( 33 )}{2 ln ( 2 )} - 9

Decimal Notation

v = - 6.47780 \dots

Solution steps

4^{v + 9} + 5 = 38

Move

5

to the right side

4^{v + 9} = 33

Apply exponent rules

(v + 9) ln (4) = ln (33)

Solve

(v + 9) ln (4) = ln (33) : v = \frac{ln ( 33 )}{2 ln ( 2 )} - 9

v = \frac{ln ( 33 )}{2 ln ( 2 )} - 9

- 10 \cdot 5^{8 - 4 x} - 7 = - 12

3^{x - 1} + 3^{x + 1} = 90

2^{4 x} = 3 2^{x - 1}

e^{x} = e^{2 x + 1}

y, x = 3^{y + 1}

What is the answer to 4^{v+9}+5=38 ?
The answer to 4^{v+9}+5=38 is v=(ln(33))/(2ln(2))-9
Solve for v: 4^{v+9}+5=38
The solution is v=(ln(33))/(2ln(2))-9