What is the answer to 3^{x-1}=5 ?

The answer to 3^{x-1}=5 is x=(ln(5))/(ln(3))+1

Solve for x: 3^{x-1}=5

The solution is x=(ln(5))/(ln(3))+1

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3^{x - 1} = 5

x = \frac{ln ( 5 )}{ln ( 3 )} + 1

Decimal Notation

x = 2.46497 \dots

Solution steps

3^{x - 1} = 5

Apply exponent rules

(x - 1) ln (3) = ln (5)

Solve

(x - 1) ln (3) = ln (5) : x = \frac{ln ( 5 )}{ln ( 3 )} + 1

x = \frac{ln ( 5 )}{ln ( 3 )} + 1

(b^{2 x - 5})^{4} = (b^{x + 5})^{3}

e^{5 x} = 20

10 0^{x} = 10

9^{x} = 2 e^{x^{2}}

2^{x - 1} = 4

What is the answer to 3^{x-1}=5 ?
The answer to 3^{x-1}=5 is x=(ln(5))/(ln(3))+1
Solve for x: 3^{x-1}=5
The solution is x=(ln(5))/(ln(3))+1