What is the answer to 2^x=0.1 ?

The answer to 2^x=0.1 is x=(ln(0.1))/(ln(2))

The solution is x=(ln(0.1))/(ln(2))

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2^x=0.1

2^{x} = 0.1

x = \frac{ln ( 0.1 )}{ln ( 2 )}

Decimal Notation

x = - 3.32192 \dots

Solution steps

2^{x} = 0.1

Apply exponent rules

x ln (2) = ln (0.1)

Solve

x ln (2) = ln (0.1) : x = \frac{ln ( 0.1 )}{ln ( 2 )}

x = \frac{ln ( 0.1 )}{ln ( 2 )}

5^{2 x + 1} = 5^{x} + 4

5 \cdot 1 0^{x} = 15

8^{x} = (\frac{1}{32})^{x - 2}

1355 = 4 5^{n}

2^{x} = 1 + x