What is the answer to 2^{x+3}=8^{x-2} ?

The answer to 2^{x+3}=8^{x-2} is x= 9/2

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2^{x+3}=8^{x-2}

2^{x + 3} = 8^{x - 2}

x = \frac{9}{2}

Decimal Notation

x = 4.5

Solution steps

2^{x + 3} = 8^{x - 2}

Apply exponent rules

x + 3 = 3 (x - 2)

Solve

x + 3 = 3 (x - 2) : x = \frac{9}{2}

x = \frac{9}{2}

4^{- x} = 64

ln (e^{x}) = 2.5

0 = 3^{x}

e^{5 x} \cdot e^{2 x} = 200 - e^{x}

5^{x + 7} = 8