What is the answer to solvefor a,2^a-2^b=2016 ?

The answer to solvefor a,2^a-2^b=2016 is a=(ln(2016+2^b))/(ln(2))

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solvefor a,2^a-2^b=2016

solve for

a, 2^{a} - 2^{b} = 2016

a = \frac{ln ( 2016 + 2 ^{b} )}{ln ( 2 )}

Solution steps

2^{a} - 2^{b} = 2016

Move

2^{b}

to the right side

2^{a} = 2016 + 2^{b}

Apply exponent rules

a ln (2) = ln (2016 + 2^{b})

Solve

a ln (2) = ln (2016 + 2^{b}) : a = \frac{ln ( 2016 + 2 ^{b} )}{ln ( 2 )}

a = \frac{ln ( 2016 + 2 ^{b} )}{ln ( 2 )}

e^{x} = e^{x}

3 (3^{x})^{2} - 4 \cdot 3^{x} = - 1

2^{x} = 2.5

8^{x - 6} = 12

e^{t^{2}} = e^{4 t - 3}

What is the answer to solvefor a,2^a-2^b=2016 ?
The answer to solvefor a,2^a-2^b=2016 is a=(ln(2016+2^b))/(ln(2))