What is the answer to 2^{x+2}=3^{x+1} ?

The answer to 2^{x+2}=3^{x+1} is x=(2ln(2)-ln(3))/(ln(3)-ln(2))

Solve for x: 2^{x+2}=3^{x+1}

The solution is x=(2ln(2)-ln(3))/(ln(3)-ln(2))

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2^{x + 2} = 3^{x + 1}

x = \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 0.70951 \dots

Solution steps

2^{x + 2} = 3^{x + 1}

Apply exponent rules

(x + 2) ln (2) = (x + 1) ln (3)

Solve

(x + 2) ln (2) = (x + 1) ln (3) : x = \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

1.5 (4)^{2 x} = 12

5^{(2 x + 1)} = 25

(\frac{1}{9})^{3 x} = 2 7^{- (x + 3)}

5 e^{x} = 36.9453

28 = 1 0^{x}

What is the answer to 2^{x+2}=3^{x+1} ?
The answer to 2^{x+2}=3^{x+1} is x=(2ln(2)-ln(3))/(ln(3)-ln(2))
Solve for x: 2^{x+2}=3^{x+1}
The solution is x=(2ln(2)-ln(3))/(ln(3)-ln(2))