What is the answer to solvefor x,3^{8x}=4^{-x-7} ?

The answer to solvefor x,3^{8x}=4^{-x-7} is x=-(7ln(2))/(ln(162))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,3^{8x}=4^{-x-7}

solve for

x, 3^{8 x} = 4^{- x - 7}

x = - \frac{7 ln ( 2 )}{ln ( 162 )}

Decimal Notation

x = - 0.95369 \dots

Solution steps

3^{8 x} = 4^{- x - 7}

Apply exponent rules

8 x ln (3) = (- x - 7) ln (4)

Solve

8 x ln (3) = (- x - 7) ln (4) : x = - \frac{7 ln ( 2 )}{ln ( 162 )}

x = - \frac{7 ln ( 2 )}{ln ( 162 )}

(\frac{3}{5})^{x} = \frac{9}{25}

6^{x + 1} - 6^{x} = 1080

4^{X + 3} \cdot 8^{2 X - 1} = 2

(\frac{1}{6})^{2 x} = 36

2 (5^{2 x - 3}) - 4 = 7

What is the answer to solvefor x,3^{8x}=4^{-x-7} ?
The answer to solvefor x,3^{8x}=4^{-x-7} is x=-(7ln(2))/(ln(162))