What is the answer to 2^{2x}=4^{x+1} ?

The answer to 2^{2x}=4^{x+1} is No Solution for x\in\mathbb{R}

Solve for x: 2^{2x}=4^{x+1}

The solution is No Solution for x\in\mathbb{R}

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2^{2 x} = 4^{x + 1}

No Solution for x \in R

Solution steps

2^{2 x} = 4^{x + 1}

Apply exponent rules

2 x = 2 (x + 1)

Solve

2 x = 2 (x + 1) :

No Solution

No Solution for x \in R

3^{x + 1} = 5^{2 x - 1}

2 e^{x + 1} = 18

x \cdot 2^{x} = 1

2^{x - 1} = \frac{1}{16}

2^{n} = 1000 \cdot 60

What is the answer to 2^{2x}=4^{x+1} ?
The answer to 2^{2x}=4^{x+1} is No Solution for x\in\mathbb{R}
Solve for x: 2^{2x}=4^{x+1}
The solution is No Solution for x\in\mathbb{R}