What is the answer to (x+1)/9-(x-1)/6 =2-(x+3)/2 ?

The answer to (x+1)/9-(x-1)/6 =2-(x+3)/2 is x= 1/2

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(x+1)/9-(x-1)/6 =2-(x+3)/2

\frac{x + 1}{9} - \frac{x - 1}{6} = 2 - \frac{x + 3}{2}

x = \frac{1}{2}

Decimal

x = 0.5

Solution steps

\frac{x + 1}{9} - \frac{x - 1}{6} = 2 - \frac{x + 3}{2}

Multiply by LCM

2 (x + 1) - 3 (x - 1) = 36 - 9 (x + 3)

Expand

2 (x + 1) - 3 (x - 1) : - x + 5

Expand

36 - 9 (x + 3) : - 9 x + 9

- x + 5 = - 9 x + 9

Move

5

to the right side

- x = - 9 x + 4

Move

9 x

to the left side

8 x = 4

Divide both sides by

8

x = \frac{1}{2}

x + 9 = 2 x + 2

\frac{1}{16} + \frac{1}{16}

16 e^{- 0.2 (5)}

a^{2} - 17 a + 42 = 0

4208

What is the answer to (x+1)/9-(x-1)/6 =2-(x+3)/2 ?
The answer to (x+1)/9-(x-1)/6 =2-(x+3)/2 is x= 1/2
Solve for x: (x+1)/9-(x-1)/6 =2-(x+3)/2
The solution is x= 1/2