What is the answer to 2(10)^x+(10)^{x+1}=4 ?

The answer to 2(10)^x+(10)^{x+1}=4 is x=-(ln(3))/(ln(10))

Solve for x: 2(10)^x+(10)^{x+1}=4

The solution is x=-(ln(3))/(ln(10))

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2 (10)^{x} + (10)^{x + 1} = 4

x = - \frac{ln ( 3 )}{ln ( 10 )}

Decimal Notation

x = - 0.47712 \dots

Solution steps

2 (10)^{x} + (10)^{x + 1} = 4

Factor

2 \cdot 1 0^{x} + 1 0^{x + 1} : 3 \cdot 5^{x} \cdot 2^{2 + x}

3 \cdot 5^{x} \cdot 2^{2 + x} = 4

Apply exponent rules

x ln (10) = ln (\frac{1}{3})

Solve

x ln (10) = ln (\frac{1}{3}) : x = - \frac{ln ( 3 )}{ln ( 10 )}

x = - \frac{ln ( 3 )}{ln ( 10 )}

e^{3 + 2 x} = 58

1 6^{x} + 1 6^{1 - x} - 10 = 0

x^{x} = 2^{16}

5^{1 - x} = 6 - 5^{x}

5 (7)^{5 x} = 60

What is the answer to 2(10)^x+(10)^{x+1}=4 ?
The answer to 2(10)^x+(10)^{x+1}=4 is x=-(ln(3))/(ln(10))
Solve for x: 2(10)^x+(10)^{x+1}=4
The solution is x=-(ln(3))/(ln(10))